Question

if thetha is equal to 60° then find the value of sin^2 thetha + cos^2 thetha + sec thetha​

Answer 1

Answer:

3

Step-by-step explanation:

$sin^2 A+cos^2A+secA\\=(sin60)^2+(cos60)^2+\frac{1}{cos60} \\=(\frac{\sqrt{3}}{2}) ^2+(\frac{1}{2})^2+\frac{1}{\frac{1}{2}}\\=\frac{3}{4}+\frac{1}{4}+2\\=\frac{3+1}{4}+2\\=\frac{4}{4}+2\\=1+2=3$