Question

If third and ninth terms of an AP are 4 and -8 respectively, which term of this AP is zero ?

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

PT = y√(1+ cot2 θ )=y√(1+(dx/dy)2 ). Also, PN = y sec q = y√(1+tan2 θ )=y√(1+(dy/dx)2 ). => Length of the normal, PN = |y| √(1+(dy/dx)2 ).