Question

if three coins are tossed find the probability of the following event.
event a getting at least one head and event b to get a head on third coin​

Answer 1

Answer:

Correct option is

A

Q,R

B

Q,P

n(S)=2×2×2=8

n(P)=HHT,HTH,THH,HHH=4,

n(Q)=TTT=1

n(R)=THT,HHH,HHT,THH=4

Q and R and P and Q are nutually exclusive as they have nothing in their intersection.

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Answer 2

Answer:

A. 0.875, B. 1/2

Step-by-step explanation:

Here, Event A = Getting at least one head.

So, Event A' = Getting no head.

Hence, P(A) = 1 - P(A') = 1 - (1/2 X 1/2 X 1/2) = 7/8 = 0.875 (apx)

It implies that the event is almost certain.

Again, Event B = Getting a head on third coin

= getting a head on a coin (since here first two coins do not affect the result)

= 1/2