twice of a number added with thrice of another number gives 23. four times the first number and 5 times the second number. when added gives 41. find the number?
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Let the 2 numbers be x and y.
According to the question
- 2x + 3y = 23 ------ [Equation 1]
- 4x + 5y = 41 ------- [Equation 2]
We need to find out the value of x and y.
Multiplying Equation 1 with 2,
2(2x + 3y) = 2(23)
→ 4x + 6y = 46 ----- [Equation 3]
Subtracting Equation 1 from Equation 3,
4x + 6y = 46
{-} 4x + 5y = 41
y = 46 - 41
So, the value if y = 5
Substitute the value of y in Equation 1 to find the value of x.
2x + 3y = 23
➝ 2x + 3(5) = 23
➝ 2x + 15 = 23
➝ 2x = 23 - 15
➝ 2x = 8
➝ x = 8 ÷ 2
➝ x = 4
So, the value of x is 5
∴ The two numbers are 5 and 4
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