Question

twice of a number added with thrice of another number gives 23. four times the first number and 5 times the second number. when added gives 41. find the number?​

Answer 1

Let the 2 numbers be x and y.

According to the question

• 2x + 3y = 23 ------ [Equation 1]
• 4x + 5y = 41 ------- [Equation 2]

We need to find out the value of x and y.

Multiplying Equation 1 with 2,

2(2x + 3y) = 2(23)

→ 4x + 6y = 46 ----- [Equation 3]

Subtracting Equation 1 from Equation 3,

4x + 6y = 46

{-} 4x + 5y = 41

y = 46 - 41

So, the value if y = 5

Substitute the value of y in Equation 1 to find the value of x.

2x + 3y = 23

➝ 2x + 3(5) = 23

➝ 2x + 15 = 23

➝ 2x = 23 - 15

➝ 2x = 8

➝ x = 8 ÷ 2

➝ x = 4

So, the value of x is 5

∴ The two numbers are 5 and 4