Question

if three coins are tossed simultaneously a. find the probability of getting one head​

Answer 1

Step-by-step explanation:

E3 = {HTT, THT, TTH} and, therefore, n(E3) = 3. Therefore, P(getting 1 head) = P(E3) = n(E3)/n(S) = 3/8.

Answer 2

Step-by-step explanation:

= 3/6

=1/2

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