Physics, asked by meenaprasad2049, 16 days ago

If three concurrent forces, each of magnitude P, are in equilibrium, the angle made by three forces with positive x- axis can be---------- a) 30 degree, 60 degree, 90 degree b) 00 degree, 90 degree, 270 degree c) 30 degree, 150 degree, 270 degree d) 00 degree, 180 degree, 270 degree​

Answers

Answered by BrainlyGovind
0

30°,60°,90°

is the correct answer

hope it helps you

Answered by durgeshbishi2
0

Answer: If three concurrent forces, each of magnitude P, are in equilibrium, the angle made by three forces with a positive x-axis can be  30 degrees, 60 degrees, and 90 degrees.

Explanation: The concurrent forces always pass through a common point.

According to Lami's theorem,  

\frac{C}{sin a} =\frac{B}{sin b} =\frac{A}{sin c}

As the magnitude of forces is the same, so: A=B=C

Thus, a=b=c

Also, a+b+c=360°

or a=b=c=\frac{360}{3} =120^{o}

As all forces have the same magnitude and the same angle between them, it will make an equilateral triangle.

So if three concurrent forces, each of magnitude P, are in equilibrium, the angle made by three forces with positive x-axis can be 30°, 60° and 90°.

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