if three consecutive multiples of 11 are multiplied by 2, 3 and 4 respectively and then added, the sum is 814. find each of the multiples
Answers
Answered by
182
Let the consecutive numbers be x, 11+x and 22+x
According to question
2x + 3(11+x) + 4(22+x) = 814
2x + 33 + 3x + 88 + 4x = 814
9x + 121 = 814
9x = 814 - 121
x = 693/9
x = 77
Multipiles are
x = 77
11 + x = 88
22 + x = 99
Hope it helps...
Answered by
75
Answer:
Let the consecutive numbers be x, 11+x and 22+x
According to question
2x + 3(11+x) + 4(22+x) = 814
2x + 33 + 3x + 88 + 4x = 814
9x + 121 = 814
9x = 814 - 121
x = 693/9
x = 77
Multipiles are
x = 77
11 + x = 88
22 + x = 99
Hope it helps...
Step-by-step explanation:
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