If three consecutive terms of A.P. are 4/5 , a , 2, then find the value of a.
Answers
Answered by
3
Heya mate ⭐
let's solve :-
given, the numbers in ap are 4/5,a,2....
then, common difference would same.
so, a-(4/5) = 2-a
=> 2a = 2 + 4/5 = 14/5
=> a = 14/10
let's solve :-
given, the numbers in ap are 4/5,a,2....
then, common difference would same.
so, a-(4/5) = 2-a
=> 2a = 2 + 4/5 = 14/5
=> a = 14/10
Answered by
4
(4/5 + 2) / 2 = a. (Arithmetic mean)
(4/5 + 10/5) / 2 = a
(14/5) / 2 = a
14/10 = a
7/5 = a
(4/5 + 10/5) / 2 = a
(14/5) / 2 = a
14/10 = a
7/5 = a
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