Question

If three consecutive terms of an A. P be 4k+8, 2k2+3k+6 and 3k2+4k+4 then find the value of k.​

Answer 1

Answer:

k=2 bruh

Step-by-step explanation:

get the difference between two consecutive terms first

so first d=2k2-k-2 and second value of d=k2+k-2

now as they both must be equal

2k2-k-2=k2+k-2

2k2-k2=k+k-2+2

k2=2k

k=2

i hope u find it helpful