Question

If three cubes are placed adjacently in a row.
Find the ratio of the total surface area of new
cuboid to that of the sum of the surface areas
of three cubes.​

Answer 1

Answer:

Explanation:

Let the side of a cube = a

TSA of one cube = 6a²

TSA of 3 such cubes = 3×6a² = 18a²

If 3 cubes are placed adjacent to each other, dimension of resulting cuboid is

→ length = 3a

→ breadth = a

→ height = a

Therefore, TSA = 2(lb+bh+lh)

= 2(3a×a + a×a + a×3a)

= 2(3a² + a² + 3a²)

= 2 × 7a²

= 14a².

Ratio = tsa of cuboid by tsa of cube

= 7:9

Hence, it is solved.

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Answer 2

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