if three cubes each of side 4 cm are placed end to end and then what are the dimensions of resulting solid
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length of cuboid =12 CM
breadth =4 cm
height = 4 cm then,
Surface area of cubiod- 2(L×B +B×H +H×L
Surface area of cubiod -2(12×4 + 4×4 + 12×4)
=2(48+16+48)
=2(108)
=216 s.q
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