If three dice are thrown simultaneously probability of getting sum as 10
Answers
Answered by
2
Three dice are thrown simultaneously.
Total no.of possible outcomes = 6³ = 216
Probability of gettinbg sum as 10 :
Favourable outcomes :
(1,3,6) (3,6,1) (3,1,6) (6,3,1) (6,1,3) (1,6,3) (1,4,5) (1,5,4) (4,5,1) (4,1,5) (5,4,1) (5,1,4) (2,3,5) (2,5,3) (3,2,5) (3,5,2) (5,3,2) (5,2,3) (2,2,6) (6,2,2) (2,6,2) (2,4,4) (4,2,4) (4,4,2) (3,3,4) (3,4,3) (4,3,3)
No.of favourable outcomes = 27
Required probability = (no.of favourable outcomes)/(total no.of possible outcomes)
= 27/216
= 1/8
Hope it helps
Total no.of possible outcomes = 6³ = 216
Probability of gettinbg sum as 10 :
Favourable outcomes :
(1,3,6) (3,6,1) (3,1,6) (6,3,1) (6,1,3) (1,6,3) (1,4,5) (1,5,4) (4,5,1) (4,1,5) (5,4,1) (5,1,4) (2,3,5) (2,5,3) (3,2,5) (3,5,2) (5,3,2) (5,2,3) (2,2,6) (6,2,2) (2,6,2) (2,4,4) (4,2,4) (4,4,2) (3,3,4) (3,4,3) (4,3,3)
No.of favourable outcomes = 27
Required probability = (no.of favourable outcomes)/(total no.of possible outcomes)
= 27/216
= 1/8
Hope it helps
Similar questions