If three distinct numbers are chosen randomly from the first 100 natural numbers, then the probability that all three of them are divisible by both 2 and 3, is
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0
Answer:
33/100
Step-by-step explanation:
because the numbers which were divisible by 2and3 there are 33 natural numbers between 100
so answer is 33/100
mahima1384:
what about multiple of 6
Answered by
0
Answer:
1/4
Step-by-step explanation:
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