If three mango are taken aftee the other from the basket which contain 10 ripe and 4 unripe mangoes
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box contains 10 mangoes out of which 4 are rotten.
Probability of taking one rotten mango =104=52
Probability of taking one good mango =106=53
If one of them is found to be good, the probability that the other is rotten is then first one is good and second is rotten or first one is rotten and second one is good =106×94+104×96=9048=158
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sorry I don't no answer
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