Question

If three numbers are in the ratio 2:3:5 and twice there sum is 100 and find the squre of the largest of three numbers.

Answer 1

Answer:

Let the no. be 2x , 3x , 5x

then,

sum of the no. is 100

so

equation is

2x +3x + 5x =100

10x = 100

x = 100/10

x = 10

the n. are 2x = 2×10 = 20

3x = 3× 10=30

5x = 5×10 = 50

largest no. = 50

square of 50 = 2500

Ans 2500

Answer 2

Answer:

625

Step-by-step explanation:

• Given twice their sum is 100. 2(2x+3x+5x)=100. 4x+6x+10x=100. 20x=100. x=5. 2(5)=10. 3(5)=15. 5(5)=25. In them the highest value is 25. square of 25 is 625