In a box, there are 8 red , 7 blue and 6 green balls . One ball is picked up randomly . What is the probability that it is neither red nor green ?
Answers
Answered by
15
Answer:
total no of balls s= 8+7+6=21
Step-by-step explanation:
let x= ball drawn is neither red or green
probability = x/s
=1/3
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Answered by
6
Answer:
the probability of ball picked is neither red nor green is equal to the probability of blue ball i.e.
7/21=1/3
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