If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is :
(A) 3/10
(B) 1/5
(C) 1/10
(D) 3/20
Answers
Answered by
0
Answer:
heyy mate
Step-by-step explanation:
maybe the answer is
D) 3/20
Answered by
0
If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is given by,
As hexagon has a total of 6 sides, we get,
Total ways of selecting 3 vertices = 6C3
Set of 3 points is equal to the 2 such sets.
The probability that the triangle formed with these chosen vertices is equilateral is
P (E) = 2 / 6C3
= 2 / [ (6 × 5 × 4) / (3 × 2 × 1) ]
= 2 / (2 × 5 × 2)
= 1 / 10
Similar questions