If three or more parallel lines are intersected by two transversals , prove that the intercepta made by them on the transversals are proportional.
Answers
Let the three parallel straight lines AB, CD, EF make equal intercepts KL and LM from the transversal IJ, that is KL = LM.
The intercepts made by these three parallel lines on the transversal XY are PQ and QR.
Construction: Through Q, a straight line is drawn parallel to IJ to intersect AB and EF at U and V respectively.
For quadrilateral KLQU,
KU ∥ LQ [∵, AB ∥ CD] and KL ∥ UQ [By construction]
∴ KLQU is a parallelogram.
∴ KL = UQ
Similarly, from quadrilateral LMVQ, we get LM = QV.
But it is given that KL = LM.
∴ UQ = QV.
Now, from △UPQ and △QVR, we get
∠PUQ = alternate ∠QVR [∵ AB ∥ EF, UV is the transversal]
∠PQU = vertically opposite ∠VQR
UQ = QV [Proved before]
∴ △UPQ ≅ △VRQ [By A-A-S condition of congruence]
∴ PQ = QR [Corresponding sides of two congruent triangles]
Thus the theorem is proved for three parallel straight line.
To prove, PQ = QR = RS.
By drawing a straight line through Q, parallel to IJ, we have proved that PO = QR.
Again, a straight line is drawn through R parallel to IJ to intersect CD and GH at Z and W a respectively.
As before, if can be proved that QR = RS.
∴ PQ = QR = RS
In this way, the theorem can be proved for any number of parallel straight lines greater than 3.
Remark: From figure 2, we get:
KL = LM = MN implies PQ = QR =RS.
∴ L is the mid point of KM.
That is, KM = 2KL.
∴ KMKL=21
or, KMMN=21 [∵ KL = MN],
∴ KM : MN = 2 : 1
Similarly from PQ = QR = RS, we get PR : RS = 2: 1
So, it can be said:
If three parallel straight lines make two intercepts from a transversal in the ratio 2 : 1, then those three parallel straight lines will make two intercepts from transversal in the ratio 2 : 1.
Likewise, in an essentially similar manner, it can be shown that if three or more parallel straight lines make intercepts from a transversal in a certain ratio, then those parallel straight lines will make intercepts from any other transversal in the same ratio.