Question

if three particles of mases 2kg,1kg,3kg are placed at corners of an equilateral triangle of perimeter 6m then the distance of centre of mass which is at origin of particles from 1kg mass is (assume 2kg on x axis)

Answer 1

2kg,3kg be on the x-axis
each side is 6m long.
co-ordinates of 1kg = (6,0)
co-ordinates of 2kg = (0,0)
co-ordinates of 3kg = (3,3*(31/2)) (pythagoras th.)
equation for co-ordinates of c.o.m.=
∑mixi/∑mi
∑miyi/∑mi
X = (1(6)+2(0)+3(3))/1+2+3 = 2.5
Y = (1(0)+2(0)+3(3*(3^1/2)))/1+2+3 = (3*(31/2))/2
co-ordinates = (2.5,(3*(31/2))/2)
Using distance formula = ((x2-x1)2+(y2-y1)2)1/2
= 9 + 6.75 = 15.75 units

Answer 2

Answer:

Explanation:

Take 1kg at origin as (0, 0)