If three resistance of 3 ohms each are connected in parallel, what will be their total resistance
Answers
Answered by
4
The series resistance is equal to 27ohms.
How?
Let the unknown resistance be equal to x.
Calculating the parallel resistance => 1/(1/x + 1/x + 1/x) = 3
From this x=9ohms.
The resistances in series are added, so 9+9+9 = 27 ohms.
How?
Let the unknown resistance be equal to x.
Calculating the parallel resistance => 1/(1/x + 1/x + 1/x) = 3
From this x=9ohms.
The resistances in series are added, so 9+9+9 = 27 ohms.
Anonymous:
okay
Which is right answer 27 or 1
if u will mark total resistance it will 27
if only parallel then 1
okay
Kk thx...nd I have ask another question anwser it plzz
plz mark as brainliest
and thanks
Fast ans that question
which
Answered by
5
Let total resistance be R'
1/R' = 1/3 + 1/3 + 1/3 = 3/3 = 1
=> R' = 1 ohm
Hence, the total resistance will be 1 ohm
Hope it helps
Mark as brainlist plz
1/R' = 1/3 + 1/3 + 1/3 = 3/3 = 1
=> R' = 1 ohm
Hence, the total resistance will be 1 ohm
Hope it helps
Mark as brainlist plz
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