Question

if three resistance of 6.9 ohm and 21 ohm are connected in series to a 12 volt battery find resistance ​

Answer 1

Solution:

From the question,

Let R1 and R2 be the given resistances.

Thus,R1=6.9Ω and R2=21Ω

Potential Difference of the battery,v:12 volts

To find:

Equivalent resistance and Current.

As the resistors are connected in series.

So, Rs=R1+R2=21+6.9=27.9Ω

Current,I:?

From ohm's law,

V=IRs

=>I=V/Rs=12/27.9=0.43A

The current flowing through the circuit is 0.43 amperes

Answer 2

so here is your answer
sry the pictures quality is not good enough