If two dice rules randomly then find probability then total sum of both dice must be less than 7
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A = { sum of both dice less than 7 }
A = {(1,1)(1,2)(1,3)(1,4)(1,5)(2,1)(2,2)(2,3)(2,4)(3,1)(3,2)(3,3)(4,1)(4,2)(5,1) }
n(A) = 15 ; n(S) = 36
p(A) = n(A)/n(S) = 15/36
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A = {(1,1)(1,2)(1,3)(1,4)(1,5)(2,1)(2,2)(2,3)(2,4)(3,1)(3,2)(3,3)(4,1)(4,2)(5,1) }
n(A) = 15 ; n(S) = 36
p(A) = n(A)/n(S) = 15/36
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the answer is 15/36
for method use Xtreme53's steps
for method use Xtreme53's steps
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