If three sides of a triangle are 6 cm, 8 cm
and 10 cm, then the altitude of the triangle
using the largest side as base will be
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in traingle ABC
take traingle ADC
AD²=AB²+DB²
AD²=5²+5²
=36+25
AD²=61
AD=√61
AD=~7.8
Did you notice that 6^2 + 8^2 = 10^2, so you have a right-angled triangle.
Sketch that triangle ABC, so that AB=8 , BC=6 and AC = 10.
draw the altitude BD, where D is on AC.
label angles A and C as x and y. Yous should notice that you have.
3 similar triangles and we can use ratios to find BD
Using ABC and BDC.
BD/8 = 6/10
BD = 48/10 = 4.8.
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