Math, asked by mahendra581, 3 months ago

The floor of a room , whose length and breadth are 6 m and 4m 20cm respectively ,is to be covered with square tiles of side 15 cm find the number of tiles required.​

Answers

Answered by shruthi2866
0

Answer:

600 tiles are required

600 tiles are requiredStep-by-step explanation:

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cm

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cm

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×Breadth

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.No. of tiles required for the floor = \frac{240000}{400}

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.No. of tiles required for the floor = \frac{240000}{400} 400

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.No. of tiles required for the floor = \frac{240000}{400} 400240000

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.No. of tiles required for the floor = \frac{240000}{400} 400240000

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.No. of tiles required for the floor = \frac{240000}{400} 400240000

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.No. of tiles required for the floor = \frac{240000}{400} 400240000 = 600600

600 tiles are requiredStep-by-step explanation:Length of floor = 6 m = 600 cmBreadth of floor = 4 m = 400 cmArea of floor = Length \times BreadthLength×BreadthArea of floor = 600 \times 400600×400Area of floor = 240000 cm^2240000cm 2 Area requires by 1 tile = 400 sq.cm.No. of tiles required for the floor = \frac{240000}{400} 400240000 = 600600Hence 600 tiles are required .

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