If three straight lines are drawn on a white board at random with the eyes closed, show that the probability of forming a triangle is 1/7.
Answers
Answer:
when u draw 3 straight lines.
there is probability of forming a triangle, 3 non parallel lines, a 3/4 rectangle, 3 intersecting lines, a 3/4 square, 3 parallel lines and 3 joint lines.
so total possibilities with 3 lines = 7
probability of triangle = 1/7
Answer:1/7
Step-by-step explanation:
S={(they form a single line i.e. they coincide each other),(they form two parallel lines i.e. two lines coincide and parallel to the other),(they form two lines intersecting lines i.e. two lines coincide and intersect with the other), (they form three lines intersecting at a point),(they form three lines which are parallel to each other),(they form three lines among them two are parallel and the other one intersect them i.e. transversal),(they form three lines and no two lines are parallel to one another i.e. they form a triangle)} let E=event of getting forming a triangle ={(they form three lines and no two lines are parallel to one another i.e. they form a triangle)} so, P(E)=1/7.
