If three times the larger of two numbers is divided by the smaller we get 4 as quotient and 8 as reminder. If five times the smaller is divi
ded by the larger we get 3 as quotientand 5 as remainder. Find the numbers
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Answered by
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Note: We know that Dividend = Divisor * Quotient + Remainder.
Let the larger number be x and the smaller number be y.
Given that 3 times, the larger number is divided by smaller we get 4 as Quotient and 8 as remainder.
= > 3x = y * 4 + 8
= > 3x = 4y + 8
= > 3x - 4y = 8 --------- (1)
Given that if five times the smaller is divided by larger we get 3 as Quotient and 5 as remainder.
= > 5y = 3x + 5
= > 5y - 3x = 5
= > -3x + 5y = 5 --------- (2)
On solving (1) & (2), we get
= > 3x - 4y = 8
= > -3x + 5y = 5
--------------------
y = 13
Substitute y = 13 in (1), we get
= > 3x - 4y = 8
= > 3x - 4(13) = 8
= > 3x - 52 = 8
= > 3x = 52 + 8
= > 3x = 60
= > x = 60/3
= > x = 20.
Therefore the numbers are 20, 13.
Verification:
= > 3 * x = 4 * y + 8
= > 3(20) = 4 * 13 + 8
= > 60 = 52 + 8
= > 60 = 60.
Hope this helps!
Let the larger number be x and the smaller number be y.
Given that 3 times, the larger number is divided by smaller we get 4 as Quotient and 8 as remainder.
= > 3x = y * 4 + 8
= > 3x = 4y + 8
= > 3x - 4y = 8 --------- (1)
Given that if five times the smaller is divided by larger we get 3 as Quotient and 5 as remainder.
= > 5y = 3x + 5
= > 5y - 3x = 5
= > -3x + 5y = 5 --------- (2)
On solving (1) & (2), we get
= > 3x - 4y = 8
= > -3x + 5y = 5
--------------------
y = 13
Substitute y = 13 in (1), we get
= > 3x - 4y = 8
= > 3x - 4(13) = 8
= > 3x - 52 = 8
= > 3x = 52 + 8
= > 3x = 60
= > x = 60/3
= > x = 20.
Therefore the numbers are 20, 13.
Verification:
= > 3 * x = 4 * y + 8
= > 3(20) = 4 * 13 + 8
= > 60 = 52 + 8
= > 60 = 60.
Hope this helps!
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