Question

If three vertices of a parallelogram ABCD are A(1,-2),B(3,6),C(5,10) , fimd the fourth vertices...
Please HELP me guys

Answer 1

so here is ur answer

Answer 2

Given three vertices of the parallelogram are A(1,-2), B(3,6) and C(5,10).

Let the coordinates of the fourth vertex be (x,y)

We know that midpoint of line segment joining the points (x1,y1) and (x2,y2) is 

(x1 + x2/2,y1 + y2/2).


Midpoint of AC = (1 + 5/2,-2+10/2)

                          = (3,4)


Midpoint of BD = (3 + x/2,6+y/2).


Now,

Midpoint of BD = Midpoint of AC.

(3 + x/2,6 + y/2) = (3,4)

3 + x/2 = 3, 6 + y/2 = 4

3 + x = 6, 6 + y = 8

x = 6 - 3,y = 8 - 6

x = 3, y = 2.


Therefore the fourth vertex is D(3,2).


Hope this helps!