if three vertices of a parallelogram abcd are a(3 -4) b(-1,-3) and c(-6,2) find the coordinate of vertex d
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Mid points of parallelogram are equal
Let d be(x, y)
Hence,
Mid point ac=3+(-6)/2,-4+2/2=(-3/2,-1)
Mid point of bd=-1+x/2,-3+y/2
ac=bd
-3/2=-1+x/2
x=-2
-1=-3+y/2
-2=-3+y
y=1
Hence your answer is (-2,1)
Let d be(x, y)
Hence,
Mid point ac=3+(-6)/2,-4+2/2=(-3/2,-1)
Mid point of bd=-1+x/2,-3+y/2
ac=bd
-3/2=-1+x/2
x=-2
-1=-3+y/2
-2=-3+y
y=1
Hence your answer is (-2,1)
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