y=sin(logx)/x plese give this an
swer
chauhandeepak:
1 is the right answer
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dy/dx={xcos(logx)1/x-sin(logx)}/x²
dy/dx={cos(logx)-sin(logx)}/x²
I hope this may be helpful for u.
dy/dx={cos(logx)-sin(logx)}/x²
I hope this may be helpful for u.
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