Chemistry, asked by king169, 1 year ago

if threshold wavelength for ejection from metal is 330nm then work function for photoelectric electron

Answers

Answered by stuti49
6
threshold frequency =c/lamda(sign)
                                =3*10^8/330*10^-9
                                =1*10^17/11 s
work func. =6.626*10^-34 *10 ^17/11
                 =6 *10^-19 j(approx)

                      
                     
                  

king169: thats not in options of this question
stuti49: oh sorry i will correct it
stuti49: is this correct or not
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