Question

If time of flight of a projectile is 10 seconds. Range is 500 meters. The maximum height attained by it will be [RPMT 1997]
A) 125 m B) 50 m C) 100 m D) 150 m

Answer 1

yeah sure for your

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Here is your answer

----> Refer to this attachment with my answer

----> Hence, Option A 125m is definetly correct answer

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Answer 2

Answer:

Maximum height attained by the projectile is 125 m

Explanation:

It is given that,

Time of flight of a projectile, T = 10 seconds

Range, R = 500 meters

We have to find the maximum height attained by the projectile.

Time of flight, $T=\dfrac{2usin\theta}{g}$

$10\ s=\dfrac{2usin\theta}{10\ m/s^2}$

$usin\theta=50\ m/s$

Maximum height reached, $h=\dfrac{u^2sin^2\theta}{2g}$

$h=\dfrac{(usin\theta)^2}{2g}$

$h=\dfrac{50^2}{2\times 10\ m/s^2}$

h = 125 meters

Hence, the correct option is (a) " 125 meters ".