two complementary angles differ by 36° find the angles
Answers
Answered by
8
let the complementary angles be x & y
x+y=90......i
A.T.Q
x-y=36.......ii
add i and ii
x+y+x-y=90+36
2x=126
x=63
putting in eq i
x+y=90
63+y=90
y=90-63.
y=27
x+y=90......i
A.T.Q
x-y=36.......ii
add i and ii
x+y+x-y=90+36
2x=126
x=63
putting in eq i
x+y=90
63+y=90
y=90-63.
y=27
Priyankagarg:
how x-y=36
Answered by
7
Hey dear!!
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Let the first unknown angle be x.
Since, the two angles differ by 36° the other angle would be (x + 36).
As in the question, they are two complementary angles. Hence, their sum would be 90°.
So the equation would be,
x + (x + 36) = 90°
2x + 36 = 90°
2x = 90 - 36
2x = 54
x = 54/2
x = 27
Therefore, the first angle measures 27° and the second angle measures 27° + 36° = 63°.
Recheck:
63° + 27° = 90° (Complementary angles)
___________________________________
Hope helped!!
________________________________
Let the first unknown angle be x.
Since, the two angles differ by 36° the other angle would be (x + 36).
As in the question, they are two complementary angles. Hence, their sum would be 90°.
So the equation would be,
x + (x + 36) = 90°
2x + 36 = 90°
2x = 90 - 36
2x = 54
x = 54/2
x = 27
Therefore, the first angle measures 27° and the second angle measures 27° + 36° = 63°.
Recheck:
63° + 27° = 90° (Complementary angles)
___________________________________
Hope helped!!
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