Question

If time of flight of a projectile is 10s range is 500m then find the maximum height attained by it

Answer 1

See it hope it will help you

Answer 2

Answer:

Answer:

Maximum height attained by the projectile is 125 m

Explanation:

It is given that,

Time of flight of a projectile, T = 10 seconds

Range, R = 500 meters

We have to find the maximum height attained by the projectile.

Time of flight, T=\dfrac{2usin\theta}{g}T=

g

2usinθ

10\ s=\dfrac{2usin\theta}{10\ m/s^2}10 s=

10 m/s

2

2usinθ

usin\theta=50\ m/susinθ=50 m/s

Maximum height reached, h=\dfrac{u^2sin^2\theta}{2g}h=

2g

u

2

sin

2

θ

h=\dfrac{(usin\theta)^2}{2g}h=

2g

(usinθ)

2

h=\dfrac{50^2}{2\times 10\ m/s^2}h=

2×10 m/s

2

50

2

h = 125 meters

Hence, the correct option is (a) " 125 meters ".