If time of flight of projectile is is less is lost range is 500 m the maximum height attained by it will be
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HI BUDDY,
■ ANSWER OF YOUR QUESTION IS 250 m
■ Hmax = Rmax/2
Therefore Hmax = 500/2
●HOPE IT WILL BE HELPFULL
SURELY COMMENT FOR FURTHER QUESTIONS
■ ANSWER OF YOUR QUESTION IS 250 m
■ Hmax = Rmax/2
Therefore Hmax = 500/2
●HOPE IT WILL BE HELPFULL
SURELY COMMENT FOR FURTHER QUESTIONS
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