Question

If tita is the acute angle between the line x+y-5=0 and 2x-y-10=0 then find the value of tan tita.​

Answer 1

tan theta = m1-m2/1+m1m2

m1=-1

M2=2

therefore

tan theta= -3/1-2

= 3

theta =taninverse 3

hope this helped you mark as beainliest

Answer 2

ANSWER :–

GIVEN LINES :–

=》 X + Y - 5 = 0 and 2 X - Y - 10 = 0

NOW –

▪︎ SLOPE OF FIRST LINE (M) = - 1

▪︎ SLOPE OF SECOND LINE (N) = 2

NOW –

${ \bold{ \implies\tan( \theta ) = | \frac{m - n}{1 + mn} | }} \\ \\ { \bold{ \implies \: \tan( \theta) = | \frac{ - 1 - 2}{1 + ( - 1)(2)} | }} \\ \\ { \bold{ \implies \tan( \theta) = | \frac{ - 3}{ - 1} | }} \\ \\ { \bold{ \implies \boxed{ \tan( \theta) = 3}}}$