Question

if Tn =5n_2 find common difference

Answer 1

Hey mate thank for the question
Hope it helps
putting the value of n =1,2,3
a1=5×1-2=5-2=3
a2=5×2-2=10-2=8
a3=5×3-2=15-2=13
So AP = 3,8,15
a=3
d=a2-a1
d=8-3
d=5

Answer 2

$\mathbf{hey \: there !} \\ \\ \\ \\ t_{n} = 5n - 2$

Substitute,
$t_{1} = 5(1) - 2 = 3$

$t_{1} = 5(2) - 2= 8$

Now, Common difference d = $t_{2} - t_{1} = 8 - 3 = 5$

Therefore, The common difference of the A. P is 5 .