If TP and TQ are the two tangents to a circle with centre O so that ∠POQ = 110°, then ∠PTQ is equal to
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In quadrilateral OPTQ
110°+90°+90°+Angle PTQ= 360°
290°+ Angle PTA =360°
Angle PTQ =360°-290°
Angle PTQ= 70°
Option (b) is correct✅✅✅
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