Question

If Trapezium abcd, side ab parallel to side CD, diagonal achi and bd intersect at point of,. If ab 20cm , dc=6cm, ob=15cm , then find id

Answer 1

Answer:

Step-by-step explanation:

From the picture we have Δ COD is similar to Δ AOB.

Since, ∠COD=∠AOB (opposite angle) , ∠CDO=∠OBA (transversal angle)  and ∠DCO=∠OAB (transversal angle).

Then  

CD /AB

= OD/ OA

​ or,

 6/20 = OD / 15

OD = 4.5

​  

 

​  

Answer 2

Answer:

From the picture we have Δ COD is similar to Δ AOB.

Since, ∠COD=∠AOB (opposite angle) , ∠CDO=∠OBA (transversal angle) and ∠DCO=∠OAB (transversal angle).

Then

AB

CD

=

OA

OD

or,

20

6

=

15

OD

or, OD=4.5