If triangle ABC are similar triangle DEF such that AB=12cm and DE =14cm .Find the ratio of areas of triangle ABC and triangle DEF
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Answers
Answered by
5
Answer:
36/49
Step-by-step explanation:
as triangle ABC is similar to triangle DEF,
SO
(AB)²/(DE)² = AREA of ABC/ area of DEF
144/196 = area of ABC/ area of DEF
36/49 = area of ABC/area of DEF
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Answered by
1
Answer:
AB=12cm
DE=14cm
AREA of triangle =1/2×base×height
In ∆ABC
Area of ∆ABC= 1/2×base×height---------eq1
= 1/2×12×height
height = 2×12
= 24cm
put the value of height in eq 1
=1/2×12×24
= 144cm²
Step-by-step explanation:
In ∆DEF
DE=14cm
Area= 1/2×base×height-----------eq2
= 1/2×14×height
height=2×14
=28cm
Area=1/2×base×height
= 1/2×14×28
=14×14
=196cm²
ratio between them
144/196=6:7
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