Question

If triangle ABC, if 3angles A=4 angle B=6 angles C, calculate angleA anglesB anglesC

Answer 1

Sol:

In ΔABC, 2∠A = 3∠B = 6 ∠C.

Let 2∠A = 3∠B = 6 ∠C = x

∠A = x/2

∠B = x/3

∠C = x/6

∠A + ∠B + ∠C = 180°

⇒ x/2 + x/3 + x/6 = 180°

⇒ (3x + 2x + x) / 6 = 180°

⇒ 6x / 6 = 180°

⇒ x = 180°

∴ ∠A = 180°/2 = 90°, ∠B = 180°/3 = 60°, ∠C = 180°/6 = 30°.