if triangle ABC is a right angled triangle where angle C=90 degrees then the value of cotA+cotB
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heya!!!
<A+<B<C=180°【 As we know 】
A+B=180°-C
cot(A+B)=cotC
=)cotA*CotB-1/cotA+cotB=cot90°
=)cotA*cotB-1/cotA+cotB=0*cotA*cotB-1
cotA+cotB=0
hope it help you.
@rajukumar☺
<A+<B<C=180°【 As we know 】
A+B=180°-C
cot(A+B)=cotC
=)cotA*CotB-1/cotA+cotB=cot90°
=)cotA*cotB-1/cotA+cotB=0*cotA*cotB-1
cotA+cotB=0
hope it help you.
@rajukumar☺
rishilaugh:
thanks
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