solve solve .......
........
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that's more easy I think .... :)
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raminder1:
wow
thats sooo interesting method
brainliest
thanks! :)
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A = i + j => |A| = √2
B = i - j => |B| = √2
Dot product of the given vectors is
A · B = (i + j) · (i - j)
= 1 - 1
= 0
Cosθ = (A · B) / ( |A||B| )
= 0 / (√2 × √2)
= 0
θ = 90°
Angle between A and B is 90°
B = i - j => |B| = √2
Dot product of the given vectors is
A · B = (i + j) · (i - j)
= 1 - 1
= 0
Cosθ = (A · B) / ( |A||B| )
= 0 / (√2 × √2)
= 0
θ = 90°
Angle between A and B is 90°
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