if triangle ABC is a right triangle,such that angle c=90 degree,angle A =45 degree & BC =7 units.Find angle B,AB & AC
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Answered by
82
we know that
angle a+b+c=180°
90°+45°+b=180°
b= 45°
given. BC =7
/_b = 45°
now tan 45° =1
in triangle abc
1=AC/7
ac =7
now sin45° =1/√2
in triangle abc
1/√2= 7/ab
ab= 7√2 meter
hence b =45° ab= 7√2 unit
ac=7 units
I hope it will help u
angle a+b+c=180°
90°+45°+b=180°
b= 45°
given. BC =7
/_b = 45°
now tan 45° =1
in triangle abc
1=AC/7
ac =7
now sin45° =1/√2
in triangle abc
1/√2= 7/ab
ab= 7√2 meter
hence b =45° ab= 7√2 unit
ac=7 units
I hope it will help u
Answered by
16
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