If triangle ABC is an isosceles triangle and angle B=65 find angle A
Answers
Answered by
3
Answer:
∠A = 50°
Step-by-step explanation:
Since Δ ABC is an isosceles triangle.
∠B = ∠C
∠B = 65°
∴ ∠C = 65°
Now,
Sum of angles of triangle = 180°
∴ ∠A + ∠B + ∠C = 180°
∠A + 65° + 65° = 180°
∠A + 130° = 180°
∠A = 180° - 130°
∠A = 50°
Angle A is 50°
Answered by
0
A + B + C = 180° (SUM OF ALL THE ANGLES OF TRIANGLE IS 180°)
65° + 65° + C = 180° (ANGLES OF CORRESPONDING EQUAL SIDES OF ISOSCELES TRIANGLE ARE EQUAL. AB =AC. B = C)
or, 130° + C = 180°
or, C = 180° - 130°
or, C = 50°
A = 65°
B = 65°
C = 50°
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