Math, asked by PB10ARSH, 4 months ago

If triangle ABC is an isosceles triangle and angle B=65 find angle A​

Answers

Answered by Sirat4
3

Answer:

∠A = 50°

Step-by-step explanation:

Since Δ ABC is an isosceles triangle.

∠B = ∠C

∠B = 65°

∴ ∠C = 65°

Now,

Sum of angles of triangle = 180°

∴ ∠A + ∠B + ∠C = 180°

  ∠A + 65° + 65° = 180°

  ∠A + 130° = 180°

  ∠A = 180° - 130°

 ∠A =  50°

Angle A is 50°

Answered by hantu14
0

A + B + C = 180° (SUM OF ALL THE ANGLES OF TRIANGLE IS 180°)

65° + 65° + C = 180° (ANGLES OF CORRESPONDING EQUAL SIDES OF ISOSCELES TRIANGLE ARE EQUAL. AB =AC. B = C)

or, 130° + C = 180°

or, C = 180° - 130°

or, C = 50°

A = 65°

B = 65°

C = 50°

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