if triangle ABC is equals to 4 cm B is equals to 7 cm C is equals to 9 CM then tanA/2
equals to
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Given : triangle ABC is equals to 4 cm B is equals to 7 cm C is equals to 9 CM
To Find : tanA/2
Solution:
a = 4 cm
b = 7 cm
c = 9 cm
a² = b² + c² − 2bc cos(A)
=> 4² = 7² + 9² - 2(7)(9)CosA
=> 16 = 49 + 81 - 126CosA
=> 114 = -126CosA
=> CosA = -114/126
=> CosA = -57/63
CosA = (1 - tan² (A/2))/(1 + tan² (A/2))
-57/63 = (1 - tan² (A/2))/(1 + tan² (A/2))
=> -57 - 57tan² (A/2) = 63 - 63tan² (A/2)
=> 6tan² (A/2) = 120
=> tan² (A/2) = 20
=> tan (A/2) = 4.47
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Step-by-step explanation:
This is the Answer 1/√20
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