Question

if triangle ABC is equilateral triangle point P is a base BC such that BC = 1.3 ABC if ab = 6 cm find AP

Answer 1

use Pythagoras theorm H^2=P^2+B^2

Answer 2

In ΔABP
AB = 6cm
BP = 1/2BC
     = 1.3/2
     =0.65

AP² = AB²-BP²  (Pythagoras theorem)
       = 6²- 0.65²
       = 36- 0.4225
      =35.5775
∴AP = √35.5775

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