if triangle ABC is right angled at C then find the value of cos A+B
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Answer:
The value of cos (A+B) is equal to 0.
Step-by-step explanation:
We know that a ""right angled triangle"" is a triangle in which one angle is “90°”
Given: ABC is a right angled triangle
i.e. A+B +C = 90⁰
Therefore A + B =180⁰ -C
=180⁰- 90⁰
A +B=90⁰
Adding Cos on both the sides [In a right angled triangle the ""cosine or cos of an angle"" is the length of side which is adjacent divided by the length of hypotenuse]
Cos(A + B)=Cos(90⁰)
=0
Step-by-step explanation:
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