Question

if triangle abc is similar to triangle edc ac is 15 bc is 10 ce is 12 to find cd​

Answer 1

by ratio of corresponding side

of similar triangle

AB/ED =BC/CD =AC/CE

BC/CD =AC/CE

10/CD=15/12

10×12=15×CD. cross multiplication

120/15=CD

CD=8

Hence CD = 8

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Answer 2

Given:

AC = 15 cm

BC = 10 cm

EC = 12 cm

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Since Tri. ABC is similar to Tri. EDC.

Therefore,

By ratio of coressponding sides-----

$\frac{ab}{ed} = \frac{bc}{dc} = \frac{ac}{ec}$

$\frac{ac}{ec} = \frac{bc}{dc} \\ \frac{15}{12} = \frac{10}{dc}$

$15dc \: = 120 \\ dc = \frac{120}{15} = 8$

Therefore... DC = 8cm

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