if triangle abc is similar to triangle pqr and ab:pq = 2:3 then area of triangle abc/area of triangle pqr?
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Step-by-step explanation:
if ∆ ABC ~ ∆pqr then
ab:PQ = 2:3
now let's take AB:PQ = 2x:3x
all the corresponding side's ratio will be 2x:3x..
area of ∆abc = 1/2 × breath × height
phythogras Therom ,
(2x)²= x²+h²
h²= 4x²-x²
h =√3x
area of ∆abc = 1/2 × √3x × 2x
= √3x²
same for ∆pqr ,but instead of 2x -> 3x
area of ∆pqr = 1/2 × √8x × 3x
= 3√8x²/2
then,area of triangle abc/area of triangle pqr is
√3x²/3√8x²/2 = 2√3:3√8...
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