Question

If triangle abc is similar to triangle qrp.Ar(abc)/ar(qrp)=9/4 and bc=15cm then find pr

Answer 1

if triangle abc similar to triangle qrp then,
area of triangle abc/area of triangle qrp=bc^2/pr^2
let pr=x
i.e.9/4=225/x^2
x^2=225×4/9
x^2=900/9
x^2=100
x=10

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